Yen had some fruits at her stall.
13 of them were kiwis,
14 of the remainder were guavas and the rest were avocados. The amounts earned for each kiwi, each guava and each avocado sold are $1.20, $1.90 and $1.80 respectively. The number of kiwis sold to the number of guavas sold to the number of avocados sold was 3 : 1 : 2. In total, she sold
13 of the fruits and earned $172.90. How many avocados did she have at first?
Kiwis |
Guavas |
Avocados |
Total |
1x2 |
2x2 |
3x2 |
|
1x1 |
3x1 |
|
2 p |
1 p |
3 p |
6 p |
The total number of guavas and avocados is repeated. Make the total number of guavas and avocados the same. LCM of 2 and 4 is 4.
|
Kiwis |
Guavas |
Avocados |
Number |
3 u |
1 u |
2 u |
Value |
$1.20 |
$1.90 |
$1.80 |
Total value |
3.6 u |
1.9 u |
3.6 u |
Total amount that Yen earned
= 3.6 u + 1.9 u + 3.6 u
= 9.1 u
9.1 u = 172.90
1 u = 172.90 ÷ 9.1 = 19
Total number of fruits sold
= 3 u + 1 u + 2 u
= 6 u
= 6 x 19
= 114
Total number of fruits at first
= 114 ÷
13= 114 x 3
= 342
Total number of fruits at first
= 2 p + 1 p + 3 p
= 6 p
6 p = 342
1 p = 342 ÷ 6 = 57
Number of avocados that Yen had at first
= 3 p
= 3 x 57
= 171
Answer(s): 171