Shiyun had some fruits at her stall.
38 of them were grapefruits,
12 of the remainder were tomatoes and the rest were dragon fruits. The amounts earned for each grapefruit, each tomato and each dragon fruit sold are $1.70, $1.50 and $1.40 respectively. The number of grapefruits sold to the number of tomatoes sold to the number of dragon fruits sold was 5 : 1 : 2. In total, she sold
14 of the fruits and earned $243.20. How many grapefruits did she have at first?
Grapefruits |
Tomatoes |
Dragon Fruits |
Total |
3x2 |
5x2 |
8x2 |
|
1x5 |
1x5 |
|
6 p |
5 p |
5 p |
16 p |
The total number of tomatoes and dragon fruits is repeated. Make the total number of tomatoes and dragon fruits the same. LCM of 5 and 2 is 10.
|
Grapefruits |
Tomatoes |
Dragon Fruits |
Number |
5 u |
1 u |
2 u |
Value |
$1.70 |
$1.50 |
$1.40 |
Total value |
8.5 u |
1.5 u |
2.8 u |
Total amount that Shiyun earned
= 8.5 u + 1.5 u + 2.8 u
= 12.8 u
12.8 u = 243.20
1 u = 243.20 ÷ 12.8 = 19
Total number of fruits sold
= 5 u + 1 u + 2 u
= 8 u
= 8 x 19
= 152
Total number of fruits at first
= 152 ÷
14= 152 x 4
= 608
Total number of fruits at first
= 6 p + 5 p + 5 p
= 16 p
16 p = 608
1 p = 608 ÷ 16 = 38
Number of grapefruits that Shiyun had at first
= 6 p
= 6 x 38
= 228
Answer(s): 228