Shannon had some fruits at her stall.
38 of them were peaches,
34 of the remainder were pomegranates and the rest were guavas. The amounts earned for each peach, each pomegranate and each guava sold are $1.10, $1.20 and $1.70 respectively. The number of peaches sold to the number of pomegranates sold to the number of guavas sold was 5 : 3 : 4. In total, she sold
116 of the fruits and earned $190.80. How many guavas did she have at first?
Peaches |
Pomegranates |
Guavas |
Total |
3x4 |
5x4 |
8x4 |
|
3x5 |
1x5 |
|
12 p |
15 p |
5 p |
32 p |
The total number of pomegranates and guavas is repeated. Make the total number of pomegranates and guavas the same. LCM of 5 and 4 is 20.
|
Peaches |
Pomegranates |
Guavas |
Number |
5 u |
3 u |
4 u |
Value |
$1.10 |
$1.20 |
$1.70 |
Total value |
5.5 u |
3.6 u |
6.8 u |
Total amount that Shannon earned
= 5.5 u + 3.6 u + 6.8 u
= 15.9 u
15.9 u = 190.80
1 u = 190.80 ÷ 15.9 = 12
Total number of fruits sold
= 5 u + 3 u + 4 u
= 12 u
= 12 x 12
= 144
Total number of fruits at first
= 144 ÷
116= 144 x 16
= 2304
Total number of fruits at first
= 12 p + 15 p + 5 p
= 32 p
32 p = 2304
1 p = 2304 ÷ 32 = 72
Number of guavas that Shannon had at first
= 5 p
= 5 x 72
= 360
Answer(s): 360