Xandra had some fruits at her stall.
13 of them were peaches,
34 of the remainder were papayas and the rest were pears. The amounts earned for each peach, each papaya and each pear sold are $1.70, $1.10 and $1.50 respectively. The number of peaches sold to the number of papayas sold to the number of pears sold was 2 : 4 : 3. In total, she sold
13 of the fruits and earned $172.20. How many peaches did she have at first?
Peaches |
Papayas |
Pears |
Total |
1x2 |
2x2 |
3x2 |
|
3x1 |
1x1 |
|
2 p |
3 p |
1 p |
6 p |
The total number of papayas and pears is repeated. Make the total number of papayas and pears the same. LCM of 2 and 4 is 4.
|
Peaches |
Papayas |
Pears |
Number |
2 u |
4 u |
3 u |
Value |
$1.70 |
$1.10 |
$1.50 |
Total value |
3.4 u |
4.4 u |
4.5 u |
Total amount that Xandra earned
= 3.4 u + 4.4 u + 4.5 u
= 12.3 u
12.3 u = 172.20
1 u = 172.20 ÷ 12.3 = 14
Total number of fruits sold
= 2 u + 4 u + 3 u
= 9 u
= 9 x 14
= 126
Total number of fruits at first
= 126 ÷
13= 126 x 3
= 378
Total number of fruits at first
= 2 p + 3 p + 1 p
= 6 p
6 p = 378
1 p = 378 ÷ 6 = 63
Number of peaches that Xandra had at first
= 2 p
= 2 x 63
= 126
Answer(s): 126