Yen had some fruits at her stall.
13 of them were lemons,
23 of the remainder were kiwis and the rest were tomatoes. The amounts earned for each lemon, each kiwi and each tomato sold are $1.10, $1.40 and $1.90 respectively. The number of lemons sold to the number of kiwis sold to the number of tomatoes sold was 5 : 2 : 5. In total, she sold
13 of the fruits and earned $53.40. How many lemons did she have at first?
Lemons |
Kiwis |
Tomatoes |
Total |
1x3 |
2x3 |
3x3 |
|
2x2 |
1x2 |
|
3 p |
4 p |
2 p |
9 p |
The total number of kiwis and tomatoes is repeated. Make the total number of kiwis and tomatoes the same. LCM of 2 and 3 is 6.
|
Lemons |
Kiwis |
Tomatoes |
Number |
5 u |
2 u |
5 u |
Value |
$1.10 |
$1.40 |
$1.90 |
Total value |
5.5 u |
2.8 u |
9.5 u |
Total amount that Yen earned
= 5.5 u + 2.8 u + 9.5 u
= 17.8 u
17.8 u = 53.40
1 u = 53.40 ÷ 17.8 = 3
Total number of fruits sold
= 5 u + 2 u + 5 u
= 12 u
= 12 x 3
= 36
Total number of fruits at first
= 36 ÷
13= 36 x 3
= 108
Total number of fruits at first
= 3 p + 4 p + 2 p
= 9 p
9 p = 108
1 p = 108 ÷ 9 = 12
Number of lemons that Yen had at first
= 3 p
= 3 x 12
= 36
Answer(s): 36