If Nicole gives Paul $14, the amount of money she has will be 80% of his. If Paul gives Nicole $7, he will have the same amount of money as her. How much money did each of them have?
(a) Paul
(b) Nicole

	Case 1		Case 2
	Paul	Nicole	Paul	Nicole
Before	5 u - 14	4 u + 14	4.5 u + 7	4.5 u - 7
Change	+ 14	- 14	- 7	+ 7
After	5 u	4 u	4.5 u	4.5 u

(a)
80% = ⁸⁰₁₀₀ = ⁴₅

In Case 1, when Nicole gives to Paul, there is an internal transfer of money from Nicole to Paul.  The total amount that both have remains the same.

In Case 2, when Paul gives to Nicole, there is an internal transfer of money from Paul to Nicole. The total amount that both have remains the same.

The total amount that both have in Case 1 and Case 2 are the same.

Total amount that Nicole and Paul have
= 5 u + 4 u
= 9 u

Amount that Nicole and Paul each has in the end for Case 2
= 9 u ÷ 2
= 4.5 u

Amount that Paul has at first is the same in Case 1 and Case 2.

5 u - 14 = 4.5 u + 7
5 u - 4.5 u = 7 + 14
0.5 u = 21 

1 u = 21 ÷ 0.5 = 42

Amount that Paul has
= 5 u - 14
= 5 x 42 - 14
= 210 - 14
= $196 

(b)
Amount that Nicole has
= 4 u + 14
= 4 x 42 + 14
= 168 + 14
= $182

Answer(s): (a) $196; (b) $182