If Irene gives Ryan $28, the amount of money she has will be 25% of his. If Ryan gives Irene $5, he will have the same amount of money as her. How much money did each of them have?
(a) Ryan
(b) Irene

	Case 1		Case 2
	Ryan	Irene	Ryan	Irene
Before	4 u - 28	1 u + 28	2.5 u + 5	2.5 u - 5
Change	+ 28	- 28	- 5	+ 5
After	4 u	1 u	2.5 u	2.5 u

(a)
25% = ²⁵₁₀₀ = ¹₄

In Case 1, when Irene gives to Ryan, there is an internal transfer of money from Irene to Ryan.  The total amount that both have remains the same.

In Case 2, when Ryan gives to Irene, there is an internal transfer of money from Ryan to Irene. The total amount that both have remains the same.

The total amount that both have in Case 1 and Case 2 are the same.

Total amount that Irene and Ryan have
= 4 u + 1 u
= 5 u

Amount that Irene and Ryan each has in the end for Case 2
= 5 u ÷ 2
= 2.5 u

Amount that Ryan has at first is the same in Case 1 and Case 2.

4 u - 28 = 2.5 u + 5
4 u - 2.5 u = 5 + 28
1.5 u = 33 

1 u = 33 ÷ 1.5 = 22

Amount that Ryan has
= 4 u - 28
= 4 x 22 - 28
= 88 - 28
= $60 

(b)
Amount that Irene has
= 1 u + 28
= 1 x 22 + 28
= 22 + 28
= $50

Answer(s): (a) $60; (b) $50