If Jade gives Lee $23, the amount of money she has will be 30% of his. If Lee gives Jade $68, he will have the same amount of money as her. How much money did each of them have?
(a) Lee
(b) Jade

	Case 1		Case 2
	Lee	Jade	Lee	Jade
Before	10 u - 23	3 u + 23	6.5 u + 68	6.5 u - 68
Change	+ 23	- 23	- 68	+ 68
After	10 u	3 u	6.5 u	6.5 u

(a)
30% = ³⁰₁₀₀ = ³₁₀

In Case 1, when Jade gives to Lee, there is an internal transfer of money from Jade to Lee.  The total amount that both have remains the same.

In Case 2, when Lee gives to Jade, there is an internal transfer of money from Lee to Jade. The total amount that both have remains the same.

The total amount that both have in Case 1 and Case 2 are the same.

Total amount that Jade and Lee have
= 10 u + 3 u
= 13 u

Amount that Jade and Lee each has in the end for Case 2
= 13 u ÷ 2
= 6.5 u

Amount that Lee has at first is the same in Case 1 and Case 2.

10 u - 23 = 6.5 u + 68
10 u - 6.5 u = 68 + 23
3.5 u = 91 

1 u = 91 ÷ 3.5 = 26

Amount that Lee has
= 10 u - 23
= 10 x 26 - 23
= 260 - 23
= $237 

(b)
Amount that Jade has
= 3 u + 23
= 3 x 26 + 23
= 78 + 23
= $101

Answer(s): (a) $237; (b) $101