If Irene gives Wesley $29, the amount of money she has will be 30% of his. If Wesley gives Irene $104, he will have the same amount of money as her. How much money did each of them have?
(a) Wesley
(b) Irene

	Case 1		Case 2
	Wesley	Irene	Wesley	Irene
Before	10 u - 29	3 u + 29	6.5 u + 104	6.5 u - 104
Change	+ 29	- 29	- 104	+ 104
After	10 u	3 u	6.5 u	6.5 u

(a)
30% = ³⁰₁₀₀ = ³₁₀

In Case 1, when Irene gives to Wesley, there is an internal transfer of money from Irene to Wesley.  The total amount that both have remains the same.

In Case 2, when Wesley gives to Irene, there is an internal transfer of money from Wesley to Irene. The total amount that both have remains the same.

The total amount that both have in Case 1 and Case 2 are the same.

Total amount that Irene and Wesley have
= 10 u + 3 u
= 13 u

Amount that Irene and Wesley each has in the end for Case 2
= 13 u ÷ 2
= 6.5 u

Amount that Wesley has at first is the same in Case 1 and Case 2.

10 u - 29 = 6.5 u + 104
10 u - 6.5 u = 104 + 29
3.5 u = 133 

1 u = 133 ÷ 3.5 = 38

Amount that Wesley has
= 10 u - 29
= 10 x 38 - 29
= 380 - 29
= $351 

(b)
Amount that Irene has
= 3 u + 29
= 3 x 38 + 29
= 114 + 29
= $143

Answer(s): (a) $351; (b) $143