If Joelle gives Jeremy $25, the amount of money she has will be 40% of his. If Jeremy gives Joelle $26, he will have the same amount of money as her. How much money did each of them have?
(a) Jeremy
(b) Joelle

	Case 1		Case 2
	Jeremy	Joelle	Jeremy	Joelle
Before	5 u - 25	2 u + 25	3.5 u + 26	3.5 u - 26
Change	+ 25	- 25	- 26	+ 26
After	5 u	2 u	3.5 u	3.5 u

(a)
40% = ⁴⁰₁₀₀ = ²₅

In Case 1, when Joelle gives to Jeremy, there is an internal transfer of money from Joelle to Jeremy.  The total amount that both have remains the same.

In Case 2, when Jeremy gives to Joelle, there is an internal transfer of money from Jeremy to Joelle. The total amount that both have remains the same.

The total amount that both have in Case 1 and Case 2 are the same.

Total amount that Joelle and Jeremy have
= 5 u + 2 u
= 7 u

Amount that Joelle and Jeremy each has in the end for Case 2
= 7 u ÷ 2
= 3.5 u

Amount that Jeremy has at first is the same in Case 1 and Case 2.

5 u - 25 = 3.5 u + 26
5 u - 3.5 u = 26 + 25
1.5 u = 51 

1 u = 51 ÷ 1.5 = 34

Amount that Jeremy has
= 5 u - 25
= 5 x 34 - 25
= 170 - 25
= $145 

(b)
Amount that Joelle has
= 2 u + 25
= 2 x 34 + 25
= 68 + 25
= $93

Answer(s): (a) $145; (b) $93