If Hilda gives Albert $37, the amount of money she has will be 30% of his. If Albert gives Hilda $110, he will have the same amount of money as her. How much money did each of them have?
(a) Albert
(b) Hilda

	Case 1		Case 2
	Albert	Hilda	Albert	Hilda
Before	10 u - 37	3 u + 37	6.5 u + 110	6.5 u - 110
Change	+ 37	- 37	- 110	+ 110
After	10 u	3 u	6.5 u	6.5 u

(a)
30% = ³⁰₁₀₀ = ³₁₀

In Case 1, when Hilda gives to Albert, there is an internal transfer of money from Hilda to Albert.  The total amount that both have remains the same.

In Case 2, when Albert gives to Hilda, there is an internal transfer of money from Albert to Hilda. The total amount that both have remains the same.

The total amount that both have in Case 1 and Case 2 are the same.

Total amount that Hilda and Albert have
= 10 u + 3 u
= 13 u

Amount that Hilda and Albert each has in the end for Case 2
= 13 u ÷ 2
= 6.5 u

Amount that Albert has at first is the same in Case 1 and Case 2.

10 u - 37 = 6.5 u + 110
10 u - 6.5 u = 110 + 37
3.5 u = 147 

1 u = 147 ÷ 3.5 = 42

Amount that Albert has
= 10 u - 37
= 10 x 42 - 37
= 420 - 37
= $383 

(b)
Amount that Hilda has
= 3 u + 37
= 3 x 42 + 37
= 126 + 37
= $163

Answer(s): (a) $383; (b) $163