If Tina gives Nick $34, the amount of money she has will be 30% of his. If Nick gives Tina $134, he will have the same amount of money as her. How much money did each of them have?
(a) Nick
(b) Tina

	Case 1		Case 2
	Nick	Tina	Nick	Tina
Before	10 u - 34	3 u + 34	6.5 u + 134	6.5 u - 134
Change	+ 34	- 34	- 134	+ 134
After	10 u	3 u	6.5 u	6.5 u

(a)
30% = ³⁰₁₀₀ = ³₁₀

In Case 1, when Tina gives to Nick, there is an internal transfer of money from Tina to Nick.  The total amount that both have remains the same.

In Case 2, when Nick gives to Tina, there is an internal transfer of money from Nick to Tina. The total amount that both have remains the same.

The total amount that both have in Case 1 and Case 2 are the same.

Total amount that Tina and Nick have
= 10 u + 3 u
= 13 u

Amount that Tina and Nick each has in the end for Case 2
= 13 u ÷ 2
= 6.5 u

Amount that Nick has at first is the same in Case 1 and Case 2.

10 u - 34 = 6.5 u + 134
10 u - 6.5 u = 134 + 34
3.5 u = 168 

1 u = 168 ÷ 3.5 = 48

Amount that Nick has
= 10 u - 34
= 10 x 48 - 34
= 480 - 34
= $446 

(b)
Amount that Tina has
= 3 u + 34
= 3 x 48 + 34
= 144 + 34
= $178

Answer(s): (a) $446; (b) $178