If Jean gives Sean $32, the amount of money she has will be 25% of his. If Sean gives Jean $25, he will have the same amount of money as her. How much money did each of them have?
(a) Sean
(b) Jean

	Case 1		Case 2
	Sean	Jean	Sean	Jean
Before	4 u - 32	1 u + 32	2.5 u + 25	2.5 u - 25
Change	+ 32	- 32	- 25	+ 25
After	4 u	1 u	2.5 u	2.5 u

(a)
25% = ²⁵₁₀₀ = ¹₄

In Case 1, when Jean gives to Sean, there is an internal transfer of money from Jean to Sean.  The total amount that both have remains the same.

In Case 2, when Sean gives to Jean, there is an internal transfer of money from Sean to Jean. The total amount that both have remains the same.

The total amount that both have in Case 1 and Case 2 are the same.

Total amount that Jean and Sean have
= 4 u + 1 u
= 5 u

Amount that Jean and Sean each has in the end for Case 2
= 5 u ÷ 2
= 2.5 u

Amount that Sean has at first is the same in Case 1 and Case 2.

4 u - 32 = 2.5 u + 25
4 u - 2.5 u = 25 + 32
1.5 u = 57 

1 u = 57 ÷ 1.5 = 38

Amount that Sean has
= 4 u - 32
= 4 x 38 - 32
= 152 - 32
= $120 

(b)
Amount that Jean has
= 1 u + 32
= 1 x 38 + 32
= 38 + 32
= $70

Answer(s): (a) $120; (b) $70