If Jaslyn gives Justin $33, the amount of money she has will be 40% of his. If Justin gives Jaslyn $12, he will have the same amount of money as her. How much money did each of them have?
(a) Justin
(b) Jaslyn

	Case 1		Case 2
	Justin	Jaslyn	Justin	Jaslyn
Before	5 u - 33	2 u + 33	3.5 u + 12	3.5 u - 12
Change	+ 33	- 33	- 12	+ 12
After	5 u	2 u	3.5 u	3.5 u

(a)
40% = ⁴⁰₁₀₀ = ²₅

In Case 1, when Jaslyn gives to Justin, there is an internal transfer of money from Jaslyn to Justin.  The total amount that both have remains the same.

In Case 2, when Justin gives to Jaslyn, there is an internal transfer of money from Justin to Jaslyn. The total amount that both have remains the same.

The total amount that both have in Case 1 and Case 2 are the same.

Total amount that Jaslyn and Justin have
= 5 u + 2 u
= 7 u

Amount that Jaslyn and Justin each has in the end for Case 2
= 7 u ÷ 2
= 3.5 u

Amount that Justin has at first is the same in Case 1 and Case 2.

5 u - 33 = 3.5 u + 12
5 u - 3.5 u = 12 + 33
1.5 u = 45 

1 u = 45 ÷ 1.5 = 30

Amount that Justin has
= 5 u - 33
= 5 x 30 - 33
= 150 - 33
= $117 

(b)
Amount that Jaslyn has
= 2 u + 33
= 2 x 30 + 33
= 60 + 33
= $93

Answer(s): (a) $117; (b) $93