If Jade gives Vaidev $36, the amount of money she has will be 10% of his. If Vaidev gives Jade $63, he will have the same amount of money as her. How much money did each of them have?
(a) Vaidev
(b) Jade

	Case 1		Case 2
	Vaidev	Jade	Vaidev	Jade
Before	10 u - 36	1 u + 36	5.5 u + 63	5.5 u - 63
Change	+ 36	- 36	- 63	+ 63
After	10 u	1 u	5.5 u	5.5 u

(a)
10% = ¹⁰₁₀₀ = ¹₁₀

In Case 1, when Jade gives to Vaidev, there is an internal transfer of money from Jade to Vaidev.  The total amount that both have remains the same.

In Case 2, when Vaidev gives to Jade, there is an internal transfer of money from Vaidev to Jade. The total amount that both have remains the same.

The total amount that both have in Case 1 and Case 2 are the same.

Total amount that Jade and Vaidev have
= 10 u + 1 u
= 11 u

Amount that Jade and Vaidev each has in the end for Case 2
= 11 u ÷ 2
= 5.5 u

Amount that Vaidev has at first is the same in Case 1 and Case 2.

10 u - 36 = 5.5 u + 63
10 u - 5.5 u = 63 + 36
4.5 u = 99 

1 u = 99 ÷ 4.5 = 22

Amount that Vaidev has
= 10 u - 36
= 10 x 22 - 36
= 220 - 36
= $184 

(b)
Amount that Jade has
= 1 u + 36
= 1 x 22 + 36
= 22 + 36
= $58

Answer(s): (a) $184; (b) $58