If Linda gives Albert $34, the amount of money she has will be 10% of his. If Albert gives Linda $128, he will have the same amount of money as her. How much money did each of them have?
(a) Albert
(b) Linda

	Case 1		Case 2
	Albert	Linda	Albert	Linda
Before	10 u - 34	1 u + 34	5.5 u + 128	5.5 u - 128
Change	+ 34	- 34	- 128	+ 128
After	10 u	1 u	5.5 u	5.5 u

(a)
10% = ¹⁰₁₀₀ = ¹₁₀

In Case 1, when Linda gives to Albert, there is an internal transfer of money from Linda to Albert.  The total amount that both have remains the same.

In Case 2, when Albert gives to Linda, there is an internal transfer of money from Albert to Linda. The total amount that both have remains the same.

The total amount that both have in Case 1 and Case 2 are the same.

Total amount that Linda and Albert have
= 10 u + 1 u
= 11 u

Amount that Linda and Albert each has in the end for Case 2
= 11 u ÷ 2
= 5.5 u

Amount that Albert has at first is the same in Case 1 and Case 2.

10 u - 34 = 5.5 u + 128
10 u - 5.5 u = 128 + 34
4.5 u = 162 

1 u = 162 ÷ 4.5 = 36

Amount that Albert has
= 10 u - 34
= 10 x 36 - 34
= 360 - 34
= $326 

(b)
Amount that Linda has
= 1 u + 34
= 1 x 36 + 34
= 36 + 34
= $70

Answer(s): (a) $326; (b) $70