If Sabrina gives Jenson $25, the amount of money she has will be 40% of his. If Jenson gives Sabrina $41, he will have the same amount of money as her. How much money did each of them have?
(a) Jenson
(b) Sabrina

	Case 1		Case 2
	Jenson	Sabrina	Jenson	Sabrina
Before	5 u - 25	2 u + 25	3.5 u + 41	3.5 u - 41
Change	+ 25	- 25	- 41	+ 41
After	5 u	2 u	3.5 u	3.5 u

(a)
40% = ⁴⁰₁₀₀ = ²₅

In Case 1, when Sabrina gives to Jenson, there is an internal transfer of money from Sabrina to Jenson.  The total amount that both have remains the same.

In Case 2, when Jenson gives to Sabrina, there is an internal transfer of money from Jenson to Sabrina. The total amount that both have remains the same.

The total amount that both have in Case 1 and Case 2 are the same.

Total amount that Sabrina and Jenson have
= 5 u + 2 u
= 7 u

Amount that Sabrina and Jenson each has in the end for Case 2
= 7 u ÷ 2
= 3.5 u

Amount that Jenson has at first is the same in Case 1 and Case 2.

5 u - 25 = 3.5 u + 41
5 u - 3.5 u = 41 + 25
1.5 u = 66 

1 u = 66 ÷ 1.5 = 44

Amount that Jenson has
= 5 u - 25
= 5 x 44 - 25
= 220 - 25
= $195 

(b)
Amount that Sabrina has
= 2 u + 25
= 2 x 44 + 25
= 88 + 25
= $113

Answer(s): (a) $195; (b) $113