If Hazel gives Henry $39, the amount of money she has will be 30% of his. If Henry gives Hazel $38, he will have the same amount of money as her. How much money did each of them have?
(a) Henry
(b) Hazel

	Case 1		Case 2
	Henry	Hazel	Henry	Hazel
Before	10 u - 39	3 u + 39	6.5 u + 38	6.5 u - 38
Change	+ 39	- 39	- 38	+ 38
After	10 u	3 u	6.5 u	6.5 u

(a)
30% = ³⁰₁₀₀ = ³₁₀

In Case 1, when Hazel gives to Henry, there is an internal transfer of money from Hazel to Henry.  The total amount that both have remains the same.

In Case 2, when Henry gives to Hazel, there is an internal transfer of money from Henry to Hazel. The total amount that both have remains the same.

The total amount that both have in Case 1 and Case 2 are the same.

Total amount that Hazel and Henry have
= 10 u + 3 u
= 13 u

Amount that Hazel and Henry each has in the end for Case 2
= 13 u ÷ 2
= 6.5 u

Amount that Henry has at first is the same in Case 1 and Case 2.

10 u - 39 = 6.5 u + 38
10 u - 6.5 u = 38 + 39
3.5 u = 77 

1 u = 77 ÷ 3.5 = 22

Amount that Henry has
= 10 u - 39
= 10 x 22 - 39
= 220 - 39
= $181 

(b)
Amount that Hazel has
= 3 u + 39
= 3 x 22 + 39
= 66 + 39
= $105

Answer(s): (a) $181; (b) $105