If Hazel gives Daniel $28, the amount of money she has will be 40% of his. If Daniel gives Hazel $8, he will have the same amount of money as her. How much money did each of them have?
(a) Daniel
(b) Hazel

	Case 1		Case 2
	Daniel	Hazel	Daniel	Hazel
Before	5 u - 28	2 u + 28	3.5 u + 8	3.5 u - 8
Change	+ 28	- 28	- 8	+ 8
After	5 u	2 u	3.5 u	3.5 u

(a)
40% = ⁴⁰₁₀₀ = ²₅

In Case 1, when Hazel gives to Daniel, there is an internal transfer of money from Hazel to Daniel.  The total amount that both have remains the same.

In Case 2, when Daniel gives to Hazel, there is an internal transfer of money from Daniel to Hazel. The total amount that both have remains the same.

The total amount that both have in Case 1 and Case 2 are the same.

Total amount that Hazel and Daniel have
= 5 u + 2 u
= 7 u

Amount that Hazel and Daniel each has in the end for Case 2
= 7 u ÷ 2
= 3.5 u

Amount that Daniel has at first is the same in Case 1 and Case 2.

5 u - 28 = 3.5 u + 8
5 u - 3.5 u = 8 + 28
1.5 u = 36 

1 u = 36 ÷ 1.5 = 24

Amount that Daniel has
= 5 u - 28
= 5 x 24 - 28
= 120 - 28
= $92 

(b)
Amount that Hazel has
= 2 u + 28
= 2 x 24 + 28
= 48 + 28
= $76

Answer(s): (a) $92; (b) $76