If Yoko gives Howard $22, the amount of money she has will be 10% of his. If Howard gives Yoko $95, he will have the same amount of money as her. How much money did each of them have?
(a) Howard
(b) Yoko

	Case 1		Case 2
	Howard	Yoko	Howard	Yoko
Before	10 u - 22	1 u + 22	5.5 u + 95	5.5 u - 95
Change	+ 22	- 22	- 95	+ 95
After	10 u	1 u	5.5 u	5.5 u

(a)
10% = ¹⁰₁₀₀ = ¹₁₀

In Case 1, when Yoko gives to Howard, there is an internal transfer of money from Yoko to Howard.  The total amount that both have remains the same.

In Case 2, when Howard gives to Yoko, there is an internal transfer of money from Howard to Yoko. The total amount that both have remains the same.

The total amount that both have in Case 1 and Case 2 are the same.

Total amount that Yoko and Howard have
= 10 u + 1 u
= 11 u

Amount that Yoko and Howard each has in the end for Case 2
= 11 u ÷ 2
= 5.5 u

Amount that Howard has at first is the same in Case 1 and Case 2.

10 u - 22 = 5.5 u + 95
10 u - 5.5 u = 95 + 22
4.5 u = 117 

1 u = 117 ÷ 4.5 = 26

Amount that Howard has
= 10 u - 22
= 10 x 26 - 22
= 260 - 22
= $238 

(b)
Amount that Yoko has
= 1 u + 22
= 1 x 26 + 22
= 26 + 22
= $48

Answer(s): (a) $238; (b) $48