Roshel has a bag containing some red and silver beads. If she removes 3 red beads, 40% of the beads in the bag are silver. If she removes another 40 silver beads, 10% of the beads in the bag are silver. How many red beads are in the bag?
| |
Red beads |
Silver beads |
| Before |
9 u + 3 |
6 u |
| Change 1 |
- 3 |
|
| After 1 |
3x3 =
9 u |
2x3 =
6 u |
| Change 2 |
|
- 40 |
| After 2 |
9x1 =
9 u |
1x1 =
1 u |
40% =
40100 =
2510% =
10100 =
110The number of red beads remains unchanged at the second change when she removes another 40 silver beads. Make the number of red beads the same at the second change. LCM of 3 and 9 is 9.
Number of silver beads removed
= 6 u - 1 u
= 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
Number of red beads at first
= 9 u + 3
= 9 x 8 + 3
= 72 + 3
= 75
Answer(s): 75
