Hilda has a bag containing some black and purple stickers. If she removes 11 black stickers, 40% of the stickers in the bag are purple. If she removes another 45 purple stickers, 10% of the stickers in the bag are purple. How many black stickers are in the bag?
|
Black stickers |
Purple stickers |
Before |
9 u + 11 |
6 u |
Change 1 |
- 11 |
|
After 1 |
3x3 = 9 u |
2x3 = 6 u |
Change 2 |
|
- 45 |
After 2 |
9x1 = 9 u |
1x1 = 1 u |
40% =
40100 =
2510% =
10100 =
110The number of black stickers remains unchanged at the second change when she removes another 45 purple stickers. Make the number of black stickers the same at the second change. LCM of 3 and 9 is 9.
Number of purple stickers removed
= 6 u - 1 u
= 5 u
5 u = 45
1 u = 45 ÷ 5 = 9
Number of black stickers at first
= 9 u + 11
= 9 x 9 + 11
= 81 + 11
= 92
Answer(s): 92