Kimberly has a bag containing some red and gold stamps. If she removes 17 red stamps, 40% of the stamps in the bag are gold. If she removes another 55 gold stamps, 10% of the stamps in the bag are gold. How many red stamps are in the bag?
| |
Red stamps |
Gold stamps |
| Before |
9 u + 17 |
6 u |
| Change 1 |
- 17 |
|
| After 1 |
3x3 =
9 u |
2x3 =
6 u |
| Change 2 |
|
- 55 |
| After 2 |
9x1 =
9 u |
1x1 =
1 u |
40% =
40100 =
2510% =
10100 =
110The number of red stamps remains unchanged at the second change when she removes another 55 gold stamps. Make the number of red stamps the same at the second change. LCM of 3 and 9 is 9.
Number of gold stamps removed
= 6 u - 1 u
= 5 u
5 u = 55
1 u = 55 ÷ 5 = 11
Number of red stamps at first
= 9 u + 17
= 9 x 11 + 17
= 99 + 17
= 116
Answer(s): 116
