A store owner has 40 more apples than persimmons. After he sold 70% of the apples and 35% of the persimmons, he is left with 9 less apples than persimmons. What fraction of the fruits left were persimmons?
|
Apples |
Persimmons |
Comparing apples and persimmons at first |
40 more |
|
Before |
10x2 = 20 u |
+ 40 |
20x1 = 20 u |
Change |
- 7x2 = - 14 u |
- 28 |
- 7x1 = - 7 u |
After |
3x2 = 6 u |
+ 12 |
13x1 = 13 u |
Comparing apples and persimmons in the end |
9 less |
|
70% =
70100 =
710 70% x 40 =
710 x 40 = 28
40 - 28 = 12
35% =
35100 =
720 The number of apples is 9 less than the number of persimmons in the end. So, if another 9 apples are added, the number of apples and persimmons in the end will be the same.
6 u + 12 + 9 = 13 u
6 u + 21 = 13 u
13 u - 6 u = 21
7 u = 21
1 u = 21 ÷ 7 = 3
Number of persimmons left
= 13 u
= 13 x 3
= 39
Total number of fruits left
= 6 u + 12 + 13 u
= 19 u + 12
= 19 x 3 + 12
= 57 + 12
= 69
Persimmons leftTotal fruits left =
3969 =
1323 Answer(s):
1323