A store owner has 32 more lemons than pears. After he sold 75% of the lemons and 20% of the pears, he is left with 124 less lemons than pears. What fraction of the fruits left were pears?
| |
Lemons |
Pears |
Comparing lemons
and pears at first |
32 more |
|
| Before |
4x5 =
20 u |
+ 32 |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 24 |
- 1x4 =
- 4 u |
| After |
1x5 =
5 u |
+ 8 |
4x4 =
16 u |
Comparing lemons
and pears in the end |
124 less |
|
75% =
75100 =
34 75% x 32 =
34 x 32 = 24
32 - 24 = 8
20% =
20100 =
15 The number of lemons is 124 less than the number of pears in the end. So, if another 124 lemons are added, the number of lemons and pears in the end will be the same.
5 u + 8 + 124 = 16 u
5 u + 132 = 16 u
16 u - 5 u = 132
11 u = 132
1 u = 132 ÷ 11 = 12
Number of pears left
= 16 u
= 16 x 12
= 192
Total number of fruits left
= 5 u + 8 + 16 u
= 21 u + 8
= 21 x 12 + 8
= 252 + 8
= 260
Pears leftTotal fruits left =
192260 =
4865 Answer(s):
4865 
