A store owner has 40 less chikoos than lemons. After he sold 80% of the chikoos and 35% of the lemons, he is left with 46 less chikoos than lemons. What fraction of the fruits left were chikoos?
|
Chikoos |
Lemons |
Comparing chikoos and lemons at first |
|
40 less |
Before |
5x4 = 20 u |
+ 40 |
20x1 = 20 u |
Change |
- 4x4 = - 16 u |
- 32 |
- 7x1 = - 7 u |
After |
1x4 = 4 u |
+ 8 |
13x1 = 13 u |
Comparing chikoos and lemons in the end |
46 less |
|
80% =
80100 =
45 80% x 40 =
45 x 40 = 32
40 - 32 = 8
35% =
35100 =
720 The number of chikoos is 46 less than the number of lemons in the end. So, if another 46 chikoos are added, the number of chikoos and lemons in the end will be the same.
4 u + 8 + 46 = 13 u
4 u + 54 = 13 u
13 u - 4 u = 54
9 u = 54
1 u = 54 ÷ 9 = 6
Number of chikoos left
= 4 u + 8
= 4 x 6 + 8
= 24 + 8
= 32
Total number of fruits left
= 4 u + 8 + 13 u
= 17 u + 8
= 17 x 6 + 8
= 102 + 8
= 110
Chikoos leftTotal fruits left =
32110 =
1655 Answer(s):
1655