A store owner has 72 more apples than oranges. After he sold 75% of the apples and 40% of the oranges, he is left with 3 less apples than oranges. What fraction of the fruits left were oranges?
| |
Apples |
Oranges |
Comparing apples
and oranges at first |
72 more |
|
| Before |
4x5 =
20 u |
+ 72 |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 54 |
- 2x4 =
- 8 u |
| After |
1x5 =
5 u |
+ 18 |
3x4 =
12 u |
Comparing apples
and oranges in the end |
3 less |
|
75% =
75100 =
34 75% x 72 =
34 x 72 = 54
72 - 54 = 18
40% =
40100 =
25 The number of apples is 3 less than the number of oranges in the end. So, if another 3 apples are added, the number of apples and oranges in the end will be the same.
5 u + 18 + 3 = 12 u
5 u + 21 = 12 u
12 u - 5 u = 21
7 u = 21
1 u = 21 ÷ 7 = 3
Number of oranges left
= 12 u
= 12 x 3
= 36
Total number of fruits left
= 5 u + 18 + 12 u
= 17 u + 18
= 17 x 3 + 18
= 51 + 18
= 69
Oranges leftTotal fruits left =
3669 =
1223 Answer(s):
1223 
