A store owner has 20 less lemons than mangoes. After he sold 70% of the lemons and 40% of the mangoes, he is left with 3 less lemons than mangoes. What fraction of the fruits left were lemons?
| |
Lemons |
Mangoes |
Comparing lemons
and mangoes at first |
|
20 less |
| Before |
10x1 =
10 u |
+ 20 |
5x2 =
10 u |
| Change |
- 7x1 =
- 7 u |
- 14 |
- 2x2 =
- 4 u |
| After |
3x1 =
3 u |
+ 6 |
3x2 =
6 u |
Comparing lemons
and mangoes in the end |
3 less |
|
70% =
70100 =
710 70% x 20 =
710 x 20 = 14
20 - 14 = 6
40% =
40100 =
25 The number of lemons is 3 less than the number of mangoes in the end. So, if another 3 lemons are added, the number of lemons and mangoes in the end will be the same.
3 u + 6 + 3 = 6 u
3 u + 9 = 6 u
6 u - 3 u = 9
3 u = 9
1 u = 9 ÷ 3 = 3
Number of lemons left
= 3 u + 6
= 3 x 3 + 6
= 9 + 6
= 15
Total number of fruits left
= 3 u + 6 + 6 u
= 9 u + 6
= 9 x 3 + 6
= 27 + 6
= 33
Lemons leftTotal fruits left =
1533 =
511 Answer(s):
511 
