A store owner has 45 more starfruits than oranges. After he sold 60% of the starfruits and 35% of the oranges, he is left with 42 less starfruits than oranges. What fraction of the fruits left were oranges?
| |
Starfruits |
Oranges |
Comparing starfruits
and oranges at first |
45 more |
|
| Before |
5x4 =
20 u |
+ 45 |
20x1 =
20 u |
| Change |
- 3x4 =
- 12 u |
- 27 |
- 7x1 =
- 7 u |
| After |
2x4 =
8 u |
+ 18 |
13x1 =
13 u |
Comparing starfruits
and oranges in the end |
42 less |
|
60% =
60100 =
35 60% x 45 =
35 x 45 = 27
45 - 27 = 18
35% =
35100 =
720 The number of starfruits is 42 less than the number of oranges in the end. So, if another 42 starfruits are added, the number of starfruits and oranges in the end will be the same.
8 u + 18 + 42 = 13 u
8 u + 60 = 13 u
13 u - 8 u = 60
5 u = 60
1 u = 60 ÷ 5 = 12
Number of oranges left
= 13 u
= 13 x 12
= 156
Total number of fruits left
= 8 u + 18 + 13 u
= 21 u + 18
= 21 x 12 + 18
= 252 + 18
= 270
Oranges leftTotal fruits left =
156270 =
2645 Answer(s):
2645 
