A store owner has 92 less oranges than kiwis. After he sold 75% of the oranges and 20% of the kiwis, he is left with 32 less oranges than kiwis. What fraction of the fruits left were oranges?
| |
Oranges |
Kiwis |
Comparing oranges
and kiwis at first |
|
92 less |
| Before |
4x5 =
20 u |
+ 92 |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 69 |
- 1x4 =
- 4 u |
| After |
1x5 =
5 u |
+ 23 |
4x4 =
16 u |
Comparing oranges
and kiwis in the end |
32 less |
|
75% =
75100 =
34 75% x 92 =
34 x 92 = 69
92 - 69 = 23
20% =
20100 =
15 The number of oranges is 32 less than the number of kiwis in the end. So, if another 32 oranges are added, the number of oranges and kiwis in the end will be the same.
5 u + 23 + 32 = 16 u
5 u + 55 = 16 u
16 u - 5 u = 55
11 u = 55
1 u = 55 ÷ 11 = 5
Number of oranges left
= 5 u + 23
= 5 x 5 + 23
= 25 + 23
= 48
Total number of fruits left
= 5 u + 23 + 16 u
= 21 u + 23
= 21 x 5 + 23
= 105 + 23
= 128
Oranges leftTotal fruits left =
48128 =
38 Answer(s):
38 
