A store owner has 68 less kiwis than mangoes. After he sold 75% of the kiwis and 10% of the mangoes, he is left with 74 less kiwis than mangoes. What fraction of the fruits left were kiwis?
| |
Kiwis |
Mangoes |
Comparing kiwis
and mangoes at first |
|
68 less |
| Before |
4x5 =
20 u |
+ 68 |
10x2 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 51 |
- 1x2 =
- 2 u |
| After |
1x5 =
5 u |
+ 17 |
9x2 =
18 u |
Comparing kiwis
and mangoes in the end |
74 less |
|
75% =
75100 =
34 75% x 68 =
34 x 68 = 51
68 - 51 = 17
10% =
10100 =
110 The number of kiwis is 74 less than the number of mangoes in the end. So, if another 74 kiwis are added, the number of kiwis and mangoes in the end will be the same.
5 u + 17 + 74 = 18 u
5 u + 91 = 18 u
18 u - 5 u = 91
13 u = 91
1 u = 91 ÷ 13 = 7
Number of kiwis left
= 5 u + 17
= 5 x 7 + 17
= 35 + 17
= 52
Total number of fruits left
= 5 u + 17 + 18 u
= 23 u + 17
= 23 x 7 + 17
= 161 + 17
= 178
Kiwis leftTotal fruits left =
52178 =
2689 Answer(s):
2689 
