A store owner has 50 more persimmons than chikoos. After he sold 70% of the persimmons and 35% of the chikoos, he is left with 20 more chikoos than persimmons. What fraction of the fruits left were chikoos?
| |
Persimmons |
Chikoos |
Comparing persimmons
and chikoos at first |
50 more |
|
| Before |
10x2 =
20 u |
+ 50 |
20x1 =
20 u |
| Change |
- 7x2 =
- 14 u |
- 35 |
- 7x1 =
- 7 u |
| After |
3x2 =
6 u |
+ 15 |
13x1 =
13 u |
Comparing persimmons
and chikoos in the end |
|
20 more |
70% =
70100 =
710 70% x 50 =
710 x 50 = 35
50 - 35 = 15
35% =
35100 =
720 The number of chikoos is 20 more than the number of persimmons in the end. So, if another 20 persimmons are added, the number of persimmons and chikoos in the end will be the same.
6 u + 15 + 20 = 13 u
6 u + 35 = 13 u
13 u - 6 u = 35
7 u = 35
1 u = 35 ÷ 7 = 5
Number of chikoos left
= 13 u
= 13 x 5
= 65
Total number of fruits left
= 6 u + 15 + 13 u
= 19 u + 15
= 19 x 5 + 15
= 95 + 15
= 110
Chikoos leftTotal fruits left =
65110 =
1322 Answer(s):
1322 
