A store owner has 80 more oranges than mangosteens. After he sold 90% of the oranges and 20% of the mangosteens, he is left with 6 more mangosteens than oranges. What fraction of the fruits left were mangosteens?
| |
Oranges |
Mangosteens |
Comparing oranges
and mangosteens at first |
80 more |
|
| Before |
10x1 =
10 u |
+ 80 |
5x2 =
10 u |
| Change |
- 9x1 =
- 9 u |
- 72 |
- 1x2 =
- 2 u |
| After |
1x1 =
1 u |
+ 8 |
4x2 =
8 u |
Comparing oranges
and mangosteens in the end |
|
6 more |
90% =
90100 =
910 90% x 80 =
910 x 80 = 72
80 - 72 = 8
20% =
20100 =
15 The number of mangosteens is 6 more than the number of oranges in the end. So, if another 6 oranges are added, the number of oranges and mangosteens in the end will be the same.
1 u + 8 + 6 = 8 u
1 u + 14 = 8 u
8 u - 1 u = 14
7 u = 14
1 u = 14 ÷ 7 = 2
Number of mangosteens left
= 8 u
= 8 x 2
= 16
Total number of fruits left
= 1 u + 8 + 8 u
= 9 u + 8
= 9 x 2 + 8
= 18 + 8
= 26
Mangosteens leftTotal fruits left =
1626 =
813 Answer(s):
813 
