A store owner has 50 less chikoos than pears. After he sold 70% of the chikoos and 40% of the pears, he is left with 9 less chikoos than pears. What fraction of the fruits left were chikoos?
| |
Chikoos |
Pears |
Comparing chikoos
and pears at first |
|
50 less |
| Before |
10x1 =
10 u |
+ 50 |
5x2 =
10 u |
| Change |
- 7x1 =
- 7 u |
- 35 |
- 2x2 =
- 4 u |
| After |
3x1 =
3 u |
+ 15 |
3x2 =
6 u |
Comparing chikoos
and pears in the end |
9 less |
|
70% =
70100 =
710 70% x 50 =
710 x 50 = 35
50 - 35 = 15
40% =
40100 =
25 The number of chikoos is 9 less than the number of pears in the end. So, if another 9 chikoos are added, the number of chikoos and pears in the end will be the same.
3 u + 15 + 9 = 6 u
3 u + 24 = 6 u
6 u - 3 u = 24
3 u = 24
1 u = 24 ÷ 3 = 8
Number of chikoos left
= 3 u + 15
= 3 x 8 + 15
= 24 + 15
= 39
Total number of fruits left
= 3 u + 15 + 6 u
= 9 u + 15
= 9 x 8 + 15
= 72 + 15
= 87
Chikoos leftTotal fruits left =
3987 =
1329 Answer(s):
1329 
