A store owner has 25 less pears than lemons. After he sold 60% of the pears and 10% of the lemons, he is left with 15 less pears than lemons. What fraction of the fruits left were pears?
| |
Pears |
Lemons |
Comparing pears
and lemons at first |
|
25 less |
| Before |
5x2 =
10 u |
+ 25 |
10x1 =
10 u |
| Change |
- 3x2 =
- 6 u |
- 15 |
- 1x1 =
- 1 u |
| After |
2x2 =
4 u |
+ 10 |
9x1 =
9 u |
Comparing pears
and lemons in the end |
15 less |
|
60% =
60100 =
35 60% x 25 =
35 x 25 = 15
25 - 15 = 10
10% =
10100 =
110 The number of pears is 15 less than the number of lemons in the end. So, if another 15 pears are added, the number of pears and lemons in the end will be the same.
4 u + 10 + 15 = 9 u
4 u + 25 = 9 u
9 u - 4 u = 25
5 u = 25
1 u = 25 ÷ 5 = 5
Number of pears left
= 4 u + 10
= 4 x 5 + 10
= 20 + 10
= 30
Total number of fruits left
= 4 u + 10 + 9 u
= 13 u + 10
= 13 x 5 + 10
= 65 + 10
= 75
Pears leftTotal fruits left =
3075 =
25 Answer(s):
25 
