A store owner has 50 more pears than starfruits. After he sold 80% of the pears and 30% of the starfruits, he is left with 20 less pears than starfruits. What fraction of the fruits left were starfruits?
| |
Pears |
Starfruits |
Comparing pears
and starfruits at first |
50 more |
|
| Before |
5x2 =
10 u |
+ 50 |
10x1 =
10 u |
| Change |
- 4x2 =
- 8 u |
- 40 |
- 3x1 =
- 3 u |
| After |
1x2 =
2 u |
+ 10 |
7x1 =
7 u |
Comparing pears
and starfruits in the end |
20 less |
|
80% =
80100 =
45 80% x 50 =
45 x 50 = 40
50 - 40 = 10
30% =
30100 =
310 The number of pears is 20 less than the number of starfruits in the end. So, if another 20 pears are added, the number of pears and starfruits in the end will be the same.
2 u + 10 + 20 = 7 u
2 u + 30 = 7 u
7 u - 2 u = 30
5 u = 30
1 u = 30 ÷ 5 = 6
Number of starfruits left
= 7 u
= 7 x 6
= 42
Total number of fruits left
= 2 u + 10 + 7 u
= 9 u + 10
= 9 x 6 + 10
= 54 + 10
= 64
Starfruits leftTotal fruits left =
4264 =
2132 Answer(s):
2132 
