A store owner has 90 more mangoes than kiwis. After he sold 90% of the mangoes and 40% of the kiwis, he is left with 6 more kiwis than mangoes. What fraction of the fruits left were kiwis?
| |
Mangoes |
Kiwis |
Comparing mangoes
and kiwis at first |
90 more |
|
| Before |
10x1 =
10 u |
+ 90 |
5x2 =
10 u |
| Change |
- 9x1 =
- 9 u |
- 81 |
- 2x2 =
- 4 u |
| After |
1x1 =
1 u |
+ 9 |
3x2 =
6 u |
Comparing mangoes
and kiwis in the end |
|
6 more |
90% =
90100 =
910 90% x 90 =
910 x 90 = 81
90 - 81 = 9
40% =
40100 =
25 The number of kiwis is 6 more than the number of mangoes in the end. So, if another 6 mangoes are added, the number of mangoes and kiwis in the end will be the same.
1 u + 9 + 6 = 6 u
1 u + 15 = 6 u
6 u - 1 u = 15
5 u = 15
1 u = 15 ÷ 5 = 3
Number of kiwis left
= 6 u
= 6 x 3
= 18
Total number of fruits left
= 1 u + 9 + 6 u
= 7 u + 9
= 7 x 3 + 9
= 21 + 9
= 30
Kiwis leftTotal fruits left =
1830 =
35 Answer(s):
35 
