A store owner has 40 less pomegranates than pears. After he sold 70% of the pomegranates and 40% of the pears, he is left with 18 less pomegranates than pears. What fraction of the fruits left were pomegranates?

	Pomegranates		Pears
Comparing pomegranates and pears at first			40 less
Before	10x1 = 10 u	+ 40	5x2 = 10 u
Change	- 7x1 = - 7 u	- 28	- 2x2 = - 4 u
After	3x1 = 3 u	+ 12	3x2 = 6 u
Comparing pomegranates  and pears in the end	18 less

70% = ⁷⁰₁₀₀ = ⁷₁₀ 
70% x 40 = ⁷₁₀ x 40 = 28
40 - 28 = 12

40% = ⁴⁰₁₀₀ = ²₅ 

The number of pomegranates is 18 less than the number of pears in the end. So, if another 18 pomegranates are added, the number of pomegranates and pears in the end will be the same.

3 u + 12 + 18 = 6 u
3 u + 30 = 6 u
6 u - 3 u = 30
3 u = 30

1 u = 30 ÷ 3 = 10

Number of pomegranates left
= 3 u + 12
= 3 x 10 + 12
= 30 + 12
= 42

Total number of fruits left
= 3 u + 12 + 6 u
= 9 u + 12
= 9 x 10 + 12
= 90 + 12
= 102

^{Pomegranates left}_{Total fruits left} = ⁴²₁₀₂ = ⁷₁₇

Answer(s): ⁷₁₇