A store owner has 100 less mangoes than lemons. After he sold 80% of the mangoes and 30% of the lemons, he is left with 5 less mangoes than lemons. What fraction of the fruits left were mangoes?
| |
Mangoes |
Lemons |
Comparing mangoes
and lemons at first |
|
100 less |
| Before |
5x2 =
10 u |
+ 100 |
10x1 =
10 u |
| Change |
- 4x2 =
- 8 u |
- 80 |
- 3x1 =
- 3 u |
| After |
1x2 =
2 u |
+ 20 |
7x1 =
7 u |
Comparing mangoes
and lemons in the end |
5 less |
|
80% =
80100 =
45 80% x 100 =
45 x 100 = 80
100 - 80 = 20
30% =
30100 =
310 The number of mangoes is 5 less than the number of lemons in the end. So, if another 5 mangoes are added, the number of mangoes and lemons in the end will be the same.
2 u + 20 + 5 = 7 u
2 u + 25 = 7 u
7 u - 2 u = 25
5 u = 25
1 u = 25 ÷ 5 = 5
Number of mangoes left
= 2 u + 20
= 2 x 5 + 20
= 10 + 20
= 30
Total number of fruits left
= 2 u + 20 + 7 u
= 9 u + 20
= 9 x 5 + 20
= 45 + 20
= 65
Mangoes leftTotal fruits left =
3065 =
613 Answer(s):
613 
