A store owner has 20 more pomegranates than oranges. After he sold 70% of the pomegranates and 40% of the oranges, he is left with 18 less pomegranates than oranges. What fraction of the fruits left were oranges?
| |
Pomegranates |
Oranges |
Comparing pomegranates
and oranges at first |
20 more |
|
| Before |
10x1 =
10 u |
+ 20 |
5x2 =
10 u |
| Change |
- 7x1 =
- 7 u |
- 14 |
- 2x2 =
- 4 u |
| After |
3x1 =
3 u |
+ 6 |
3x2 =
6 u |
Comparing pomegranates
and oranges in the end |
18 less |
|
70% =
70100 =
710 70% x 20 =
710 x 20 = 14
20 - 14 = 6
40% =
40100 =
25 The number of pomegranates is 18 less than the number of oranges in the end. So, if another 18 pomegranates are added, the number of pomegranates and oranges in the end will be the same.
3 u + 6 + 18 = 6 u
3 u + 24 = 6 u
6 u - 3 u = 24
3 u = 24
1 u = 24 ÷ 3 = 8
Number of oranges left
= 6 u
= 6 x 8
= 48
Total number of fruits left
= 3 u + 6 + 6 u
= 9 u + 6
= 9 x 8 + 6
= 72 + 6
= 78
Oranges leftTotal fruits left =
4878 =
813 Answer(s):
813 
