A store owner has 30 more pears than starfruits. After he sold 60% of the pears and 35% of the starfruits, he is left with 38 less pears than starfruits. What fraction of the fruits left were starfruits?
| |
Pears |
Starfruits |
Comparing pears
and starfruits at first |
30 more |
|
| Before |
5x4 =
20 u |
+ 30 |
20x1 =
20 u |
| Change |
- 3x4 =
- 12 u |
- 18 |
- 7x1 =
- 7 u |
| After |
2x4 =
8 u |
+ 12 |
13x1 =
13 u |
Comparing pears
and starfruits in the end |
38 less |
|
60% =
60100 =
35 60% x 30 =
35 x 30 = 18
30 - 18 = 12
35% =
35100 =
720 The number of pears is 38 less than the number of starfruits in the end. So, if another 38 pears are added, the number of pears and starfruits in the end will be the same.
8 u + 12 + 38 = 13 u
8 u + 50 = 13 u
13 u - 8 u = 50
5 u = 50
1 u = 50 ÷ 5 = 10
Number of starfruits left
= 13 u
= 13 x 10
= 130
Total number of fruits left
= 8 u + 12 + 13 u
= 21 u + 12
= 21 x 10 + 12
= 210 + 12
= 222
Starfruits leftTotal fruits left =
130222 =
65111 Answer(s):
65111 
