A store owner has 60 more mangosteens than pears. After he sold 80% of the mangosteens and 35% of the pears, he is left with 24 less mangosteens than pears. What fraction of the fruits left were pears?
| |
Mangosteens |
Pears |
Comparing mangosteens
and pears at first |
60 more |
|
| Before |
5x4 =
20 u |
+ 60 |
20x1 =
20 u |
| Change |
- 4x4 =
- 16 u |
- 48 |
- 7x1 =
- 7 u |
| After |
1x4 =
4 u |
+ 12 |
13x1 =
13 u |
Comparing mangosteens
and pears in the end |
24 less |
|
80% =
80100 =
45 80% x 60 =
45 x 60 = 48
60 - 48 = 12
35% =
35100 =
720 The number of mangosteens is 24 less than the number of pears in the end. So, if another 24 mangosteens are added, the number of mangosteens and pears in the end will be the same.
4 u + 12 + 24 = 13 u
4 u + 36 = 13 u
13 u - 4 u = 36
9 u = 36
1 u = 36 ÷ 9 = 4
Number of pears left
= 13 u
= 13 x 4
= 52
Total number of fruits left
= 4 u + 12 + 13 u
= 17 u + 12
= 17 x 4 + 12
= 68 + 12
= 80
Pears leftTotal fruits left =
5280 =
1320 Answer(s):
1320 
