A store owner has 70 less pomegranates than apples. After he sold 60% of the pomegranates and 10% of the apples, he is left with 7 less pomegranates than apples. What fraction of the fruits left were pomegranates?
|
Pomegranates |
Apples |
Comparing pomegranates and apples at first |
|
70 less |
Before |
5x2 = 10 u |
+ 70 |
10x1 = 10 u |
Change |
- 3x2 = - 6 u |
- 42 |
- 1x1 = - 1 u |
After |
2x2 = 4 u |
+ 28 |
9x1 = 9 u |
Comparing pomegranates and apples in the end |
7 less |
|
60% =
60100 =
35 60% x 70 =
35 x 70 = 42
70 - 42 = 28
10% =
10100 =
110 The number of pomegranates is 7 less than the number of apples in the end. So, if another 7 pomegranates are added, the number of pomegranates and apples in the end will be the same.
4 u + 28 + 7 = 9 u
4 u + 35 = 9 u
9 u - 4 u = 35
5 u = 35
1 u = 35 ÷ 5 = 7
Number of pomegranates left
= 4 u + 28
= 4 x 7 + 28
= 28 + 28
= 56
Total number of fruits left
= 4 u + 28 + 9 u
= 13 u + 28
= 13 x 7 + 28
= 91 + 28
= 119
Pomegranates leftTotal fruits left =
56119 =
817 Answer(s):
817