A store owner has 40 less chikoos than pears. After he sold 60% of the chikoos and 30% of the pears, he is left with 20 less chikoos than pears. What fraction of the fruits left were chikoos?
|
Chikoos |
Pears |
Comparing chikoos and pears at first |
|
40 less |
Before |
5x2 = 10 u |
+ 40 |
10x1 = 10 u |
Change |
- 3x2 = - 6 u |
- 24 |
- 3x1 = - 3 u |
After |
2x2 = 4 u |
+ 16 |
7x1 = 7 u |
Comparing chikoos and pears in the end |
20 less |
|
60% =
60100 =
35 60% x 40 =
35 x 40 = 24
40 - 24 = 16
30% =
30100 =
310 The number of chikoos is 20 less than the number of pears in the end. So, if another 20 chikoos are added, the number of chikoos and pears in the end will be the same.
4 u + 16 + 20 = 7 u
4 u + 36 = 7 u
7 u - 4 u = 36
3 u = 36
1 u = 36 ÷ 3 = 12
Number of chikoos left
= 4 u + 16
= 4 x 12 + 16
= 48 + 16
= 64
Total number of fruits left
= 4 u + 16 + 7 u
= 11 u + 16
= 11 x 12 + 16
= 132 + 16
= 148
Chikoos leftTotal fruits left =
64148 =
1637 Answer(s):
1637