A store owner has 44 more oranges than lemons. After he sold 75% of the oranges and 20% of the lemons, he is left with 110 more lemons than oranges. What fraction of the fruits left were lemons?
| |
Oranges |
Lemons |
Comparing oranges
and lemons at first |
44 more |
|
| Before |
4x5 =
20 u |
+ 44 |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 33 |
- 1x4 =
- 4 u |
| After |
1x5 =
5 u |
+ 11 |
4x4 =
16 u |
Comparing oranges
and lemons in the end |
|
110 more |
75% =
75100 =
34 75% x 44 =
34 x 44 = 33
44 - 33 = 11
20% =
20100 =
15 The number of lemons is 110 more than the number of oranges in the end. So, if another 110 oranges are added, the number of oranges and lemons in the end will be the same.
5 u + 11 + 110 = 16 u
5 u + 121 = 16 u
16 u - 5 u = 121
11 u = 121
1 u = 121 ÷ 11 = 11
Number of lemons left
= 16 u
= 16 x 11
= 176
Total number of fruits left
= 5 u + 11 + 16 u
= 21 u + 11
= 21 x 11 + 11
= 231 + 11
= 242
Lemons leftTotal fruits left =
176242 =
811 Answer(s):
811 
