A store owner has 90 more mangoes than mangosteens. After he sold 90% of the mangoes and 20% of the mangosteens, he is left with 12 less mangoes than mangosteens. What fraction of the fruits left were mangosteens?
| |
Mangoes |
Mangosteens |
Comparing mangoes
and mangosteens at first |
90 more |
|
| Before |
10x1 =
10 u |
+ 90 |
5x2 =
10 u |
| Change |
- 9x1 =
- 9 u |
- 81 |
- 1x2 =
- 2 u |
| After |
1x1 =
1 u |
+ 9 |
4x2 =
8 u |
Comparing mangoes
and mangosteens in the end |
12 less |
|
90% =
90100 =
910 90% x 90 =
910 x 90 = 81
90 - 81 = 9
20% =
20100 =
15 The number of mangoes is 12 less than the number of mangosteens in the end. So, if another 12 mangoes are added, the number of mangoes and mangosteens in the end will be the same.
1 u + 9 + 12 = 8 u
1 u + 21 = 8 u
8 u - 1 u = 21
7 u = 21
1 u = 21 ÷ 7 = 3
Number of mangosteens left
= 8 u
= 8 x 3
= 24
Total number of fruits left
= 1 u + 9 + 8 u
= 9 u + 9
= 9 x 3 + 9
= 27 + 9
= 36
Mangosteens leftTotal fruits left =
2436 =
23 Answer(s):
23 
