A store owner has 90 less pears than pomegranates. After he sold 90% of the pears and 35% of the pomegranates, he is left with 13 less pears than pomegranates. What fraction of the fruits left were pears?
| |
Pears |
Pomegranates |
Comparing pears
and pomegranates at first |
|
90 less |
| Before |
10x2 =
20 u |
+ 90 |
20x1 =
20 u |
| Change |
- 9x2 =
- 18 u |
- 81 |
- 7x1 =
- 7 u |
| After |
1x2 =
2 u |
+ 9 |
13x1 =
13 u |
Comparing pears
and pomegranates in the end |
13 less |
|
90% =
90100 =
910 90% x 90 =
910 x 90 = 81
90 - 81 = 9
35% =
35100 =
720 The number of pears is 13 less than the number of pomegranates in the end. So, if another 13 pears are added, the number of pears and pomegranates in the end will be the same.
2 u + 9 + 13 = 13 u
2 u + 22 = 13 u
13 u - 2 u = 22
11 u = 22
1 u = 22 ÷ 11 = 2
Number of pears left
= 2 u + 9
= 2 x 2 + 9
= 4 + 9
= 13
Total number of fruits left
= 2 u + 9 + 13 u
= 15 u + 9
= 15 x 2 + 9
= 30 + 9
= 39
Pears leftTotal fruits left =
1339 =
13 Answer(s):
13 
