A store owner has 80 more oranges than apples. After he sold 80% of the oranges and 30% of the apples, he is left with 34 less oranges than apples. What fraction of the fruits left were apples?
| |
Oranges |
Apples |
Comparing oranges
and apples at first |
80 more |
|
| Before |
5x2 =
10 u |
+ 80 |
10x1 =
10 u |
| Change |
- 4x2 =
- 8 u |
- 64 |
- 3x1 =
- 3 u |
| After |
1x2 =
2 u |
+ 16 |
7x1 =
7 u |
Comparing oranges
and apples in the end |
34 less |
|
80% =
80100 =
45 80% x 80 =
45 x 80 = 64
80 - 64 = 16
30% =
30100 =
310 The number of oranges is 34 less than the number of apples in the end. So, if another 34 oranges are added, the number of oranges and apples in the end will be the same.
2 u + 16 + 34 = 7 u
2 u + 50 = 7 u
7 u - 2 u = 50
5 u = 50
1 u = 50 ÷ 5 = 10
Number of apples left
= 7 u
= 7 x 10
= 70
Total number of fruits left
= 2 u + 16 + 7 u
= 9 u + 16
= 9 x 10 + 16
= 90 + 16
= 106
Apples leftTotal fruits left =
70106 =
3553 Answer(s):
3553 
