A store owner has 45 less persimmons than lemons. After he sold 60% of the persimmons and 10% of the lemons, he is left with 22 less persimmons than lemons. What fraction of the fruits left were persimmons?

	Persimmons		Lemons
Comparing persimmons and lemons at first			45 less
Before	5x2 = 10 u	+ 45	10x1 = 10 u
Change	- 3x2 = - 6 u	- 27	- 1x1 = - 1 u
After	2x2 = 4 u	+ 18	9x1 = 9 u
Comparing persimmons  and lemons in the end	22 less

60% = ⁶⁰₁₀₀ = ³₅ 
60% x 45 = ³₅ x 45 = 27
45 - 27 = 18

10% = ¹⁰₁₀₀ = ¹₁₀ 

The number of persimmons is 22 less than the number of lemons in the end. So, if another 22 persimmons are added, the number of persimmons and lemons in the end will be the same.

4 u + 18 + 22 = 9 u
4 u + 40 = 9 u
9 u - 4 u = 40
5 u = 40

1 u = 40 ÷ 5 = 8

Number of persimmons left
= 4 u + 18
= 4 x 8 + 18
= 32 + 18
= 50

Total number of fruits left
= 4 u + 18 + 9 u
= 13 u + 18
= 13 x 8 + 18
= 104 + 18
= 122

^{Persimmons left}_{Total fruits left} = ⁵⁰₁₂₂ = ²⁵₆₁

Answer(s): ²⁵₆₁