A store owner has 20 more oranges than pomegranates. After he sold 80% of the oranges and 10% of the pomegranates, he is left with 38 less oranges than pomegranates. What fraction of the fruits left were pomegranates?
| |
Oranges |
Pomegranates |
Comparing oranges
and pomegranates at first |
20 more |
|
| Before |
5x2 =
10 u |
+ 20 |
10x1 =
10 u |
| Change |
- 4x2 =
- 8 u |
- 16 |
- 1x1 =
- 1 u |
| After |
1x2 =
2 u |
+ 4 |
9x1 =
9 u |
Comparing oranges
and pomegranates in the end |
38 less |
|
80% =
80100 =
45 80% x 20 =
45 x 20 = 16
20 - 16 = 4
10% =
10100 =
110 The number of oranges is 38 less than the number of pomegranates in the end. So, if another 38 oranges are added, the number of oranges and pomegranates in the end will be the same.
2 u + 4 + 38 = 9 u
2 u + 42 = 9 u
9 u - 2 u = 42
7 u = 42
1 u = 42 ÷ 7 = 6
Number of pomegranates left
= 9 u
= 9 x 6
= 54
Total number of fruits left
= 2 u + 4 + 9 u
= 11 u + 4
= 11 x 6 + 4
= 66 + 4
= 70
Pomegranates leftTotal fruits left =
5470 =
2735 Answer(s):
2735 
